reduction mod p

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reduction mod p

For \(K = {\mathbf{Q}}\) and $V \in {\mathsf{Sch}}_{/ {\operatorname{Spec}{\mathbf{Z}}}} $, reduction \(\operatorname{mod}p\) is pulling back:

Link to Diagram

  • This works for almost all \(p\) and corresponds to reducing the coefficients \(\operatorname{mod}p\).
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