finite type

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finite type

Ideas:

  • Finite type: fibers of finite dimension.
  • Finite: proper and finite type, so like a branched cover

For rings/algebras

Recall that $f\in \mathsf{CRing}(B, A) \leadsto A\in \mathsf{Alg} _{/ {B}} $.

  • \(A\in \mathsf{Alg} _{/ {B}} ^{\mathrm{ft}}\) is an algebra of finite type iff \(A\) is finitely generated as an algebra over \(B\).
  • \(A\in \mathsf{Alg} _{/ {B}} ^{\mathrm{fin}}\) is a finite algebra iff \(A\) is finitely generated as an module over \(B\).

So define a morphism of rings \(B\to A\) to be finite type if it makes \(A\) a finite type algebra and finite if it makes \(A\) a finite algebra.

  • Note that being a finite algebra is stronger than being finite type algebra.

For schemes

A morphism \(f\in {\mathsf{Sch}}(X, Y)\) is locally of finite type iff for every open \(\operatorname{Spec}B \subseteq Y\), there is a cover \(\left\{{\operatorname{Spec}A_i}\right\}_{i\in I}\rightrightarrows f^{-1}(\operatorname{Spec}B)\) where the induced ring morphisms \(f_i^*\in \mathsf{CRing}(B, A_i)\) are finite type as above. A morphism \(f\) is finite if the \(f_i^*\) are finite ring morphisms, or equivalently \(f\) is locally of finite type and the above cover can be chosen to be finite.

  • So \(f\in {\mathsf{Sch}}(X, Y)\) is
    • Locally of finite type iff \(f_i^*\in \mathsf{CRing}(B, A_i)\) are finite type iff \(A_i \in \mathsf{Alg} _{/ {B}} ^{\mathrm{ft}}\) (finite generation as algebras)
    • Finite iff \(f_i^*\in \mathsf{CRing}(B, A_i)\) are finite iff \(A_i\in \mathsf{Alg} _{/ {B}} ^{\mathrm{fg}}\) (finite generation as modules)
  • Some equivalent characterizations of locally of finite type morphisms:
    • The ring morphism \({\mathcal{O}}_X(V) \to {\mathcal{O}}_X(U)\) is finite type for every \(U \subseteq X, V\subseteq Y\) with \(f(U) \subseteq V\)
  • Equivalently: a relative scheme \(f:X\to Y\) is finite type iff there is an affine open cover of \(Y\) by \(U_i = \operatorname{Spec}S_i\) where each \(f^{-1}(U_i)\) admits a finite open cover by affine schemes \(\operatorname{Spec}R_{ij}\) where each \(R_{ij}\) is a finitely-generated \(S_i{\hbox{-}}\)algebra.

attachments/Pasted%20image%2020220418115730.png

Examples

  • There are finite type but non-finite algebras: \begin{align*} k[x_1, \cdots, x_{n}]\in \mathsf{Alg} _{/ {k}} ^{\mathrm{ft}}\setminus \mathsf{Alg} _{/ {k}} ^{\mathrm{fin}} \end{align*} So ${\mathbf{A}}^n_{/ {k}} $ is finite type over \(k\) but not finite.

  • Any quasiprojective object in ${\mathsf{Sch}}_{/ {k}} $ is finite type over \(k\).

  • Noether normalization: if \(X\in {\mathsf{Aff}}{\mathsf{Sch}}_{/ {k}} ^{\mathrm{ft}}\), then there is a finite surjective morphism $X\twoheadrightarrow{\mathbf{A}}^d_{/ {k}} $ where \(d\coloneqq\dim X\). attachments/Pasted%20image%2020220417014434.png

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