12:47
Tags: #category_theory #homotopy_theory
mapping cone as a pushout and mapping fiber as pullback :
- Mf→X→Y yields a LES in homotopy π∗Mf→π∗X→π∗Y.
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X→Y→Cf yields π∗(Y,X)=π∗−1Cf?
- This should be an easy consequence of the LES in homotopy.
Probability Review
Tags: #probability #review_material #undergraduate
- Binomial and Poisson distributions tend to normal distributions?
- Normal distribution rule: 68, 95, 99.7.
- E[r(x)]:=∫r(x)f(x)dxor ∑kr(k)P(x=k).
- Var(x)=E[x2]−E2[x]
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Marginal densities: if f(x,y) is a distribution,
fx(x):=∫f(x,y)dyP(x×y∈A)=∬Af(x,y)dxdy.
- Independent if f(x,y)=fx(x)fy(y).
- If x has density fx and y:=r(x) for a continuous increasing function, setting s:=r−1, y has density gy(y)=fx(s(y))s′(y).
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Given a failure rate λ in failures over time and a time span t, the probability of failing k times in t units of time is Poisson(λt).
- The time between failures is Exponential(λ).
Combinatorics Review
Tags: #combinatorics #review_material #undergraduate
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Prop: the number of integer compositions of n into exactly k parts is (n−1k−1), so ∑ai=n with ai≥1 for all i.
- Lay out n copies of 1 with n−1 blanks between them. Choose to put a plus sign or a comma in each slot: choose k−1 commas to produce k blocks.
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Prop: the number of compositions of n into any number of parts is 2n−1.
- Sum over compositions with exactly k parts and use the identity ∑n−1k=1(n−1k−1)=2n−1.
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Prop: the number of weak compositions of n into exactly k parts is (n+k−1k−1).
- Add one to each piece to get a (strong) composition of n+k into k parts.
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Quotient set of compositions by permutations to get integer partitions.
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Stirling numbers : the number of ways to partition an n element set into exactly k nonempty unlabeled disjoint blocks whose disjoint union is the original set.
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Prop: recurrence for partitions :
s(n+1,k)=s(n,k−1)+ks(n,k).
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Proof: check if a given partition of n+1 into k parts contains the singleton {n+1}.
- If so, delete and count partitions of n into k−1 parts.
- If not, add {n+1} to any of the k parts.
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Proof: check if a given partition of n+1 into k parts contains the singleton {n+1}.
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Prop: recurrence for partitions :
s(n+1,k)=s(n,k−1)+ks(n,k).