2021-06-22

12:47

Tags: #category_theory #homotopy_theory

mapping cone as a pushout and mapping fiber as pullback :

Link to Diagram

  • MfXY yields a LES in homotopy πMfπXπY.
  • XYCf yields π(Y,X)=π1Cf?
    • This should be an easy consequence of the LES in homotopy.

Probability Review

Tags: #probability #review_material #undergraduate

Link to Diagram

  • Binomial and Poisson distributions tend to normal distributions?
  • Normal distribution rule: 68, 95, 99.7.
  • E[r(x)]:=r(x)f(x)dxor kr(k)P(x=k).
  • Var(x)=E[x2]E2[x]
  • Marginal densities: if f(x,y) is a distribution, fx(x):=f(x,y)dyP(x×yA)=Af(x,y)dxdy.
    • Independent if f(x,y)=fx(x)fy(y).
  • If x has density fx and y:=r(x) for a continuous increasing function, setting s:=r1, y has density gy(y)=fx(s(y))s(y).
  • Given a failure rate λ in failures over time and a time span t, the probability of failing k times in t units of time is Poisson(λt).
    • The time between failures is Exponential(λ).

Combinatorics Review

Tags: #combinatorics #review_material #undergraduate

  • Prop: the number of integer compositions of n into exactly k parts is (n1k1), so ai=n with ai1 for all i.

    • Lay out n copies of 1 with n1 blanks between them. Choose to put a plus sign or a comma in each slot: choose k1 commas to produce k blocks.
  • Prop: the number of compositions of n into any number of parts is 2n1.

    • Sum over compositions with exactly k parts and use the identity n1k=1(n1k1)=2n1.
  • Prop: the number of weak compositions of n into exactly k parts is (n+k1k1).

    • Add one to each piece to get a (strong) composition of n+k into k parts.
  • Quotient set of compositions by permutations to get integer partitions.

  • Stirling numbers : the number of ways to partition an n element set into exactly k nonempty unlabeled disjoint blocks whose disjoint union is the original set.

    • Prop: recurrence for partitions : s(n+1,k)=s(n,k1)+ks(n,k).
      • Proof: check if a given partition of n+1 into k parts contains the singleton {n+1}.
        • If so, delete and count partitions of n into k1 parts.
        • If not, add {n+1} to any of the k parts.
#quick_notes #category_theory #homotopy_theory #probability #review_material #undergraduate #combinatorics